Number of sacks of cement required for a given length of plug

Input(s)

$\mathrm{L}_{\mathrm{p}}$: Plug Length (ft)

$\mathrm{C}_{\mathrm{c}}$: Casing Capacity $\left(\mathrm{ft}^{3} / \mathrm{ft}\right)$

E: Excess Volume (fraction)

Y: Slurry Yield $\left(\mathrm{ft}^{3} /\right.$ stroke $)$

Output(s)

$\mathrm{N}_{\mathrm{s}}$: Sacks of Cement Required (unitless)

Formula(s)

$$ \mathrm{N}_{\mathrm{s}}=\frac{\mathrm{L}_{\mathrm{p}} * \mathrm{C}_{\mathrm{c}} * \mathrm{E}}{\mathrm{Y}} $$

Reference(s)

Lapeyrouse, N. J., 2002, Formulas and Calculations for Drilling, Production and Workover, Second Edition, Gulf Professional Publishing, Page: 61.