Equivalent area of pipe subject to uniform axial force

Input(s)

$\mathrm{A}_{\mathrm{b}}$: Area of Body $\left(\right.$ in. $\left.^{2}\right)$

$\mathrm{A}_{\mathrm{j}}$: Area of Joint ( in. ${ }^{2}$ )

$\alpha$: Length Factor for Pipe Body (fraction)

Output(s)

$A_{p}$ :Area of Pipe ( in. ${ }^{2}$ )

Formula(s)

$$ \mathrm{A}_{\mathrm{p}}=\frac{\mathrm{A}_{\mathrm{b}} * \mathrm{~A}_{\mathrm{j}}}{\alpha * \mathrm{~A}_{\mathrm{b}} *(1-\alpha) * \mathrm{~A}_{\mathrm{j}}} $$

Reference(s)

Samuel. E Robello. 501 Solved Problems and Calculations for Drilling Operations. Sigma Quadrant. 2015. Houston, Texas, Page: 44.