Dimensionless time - Myhill and Stegemeier's method

Input(s)

$\mathrm{M}_{\mathrm{s}}$: Volumetric Heat Capacity of Steam $\left(\mathrm{btu} / \mathrm{ft}^{3} \mathrm{~K}\right)$

$\mathrm{M}_{\mathrm{R}}$: Volumetric Heat Capacity of the Reservoir (btu/ft $\mathrm{ft}^{3} \mathrm{~K}$ )

$\alpha_{\mathrm{s}}$: Overburden Heat Transfer Coefficient $\left(\mathrm{ft}^{2} / \mathrm{d}\right)$

$\mathrm{h}_{\mathrm{t}}$: Thickness of Column (ft)

t: Time (day)

Output(s)

$\mathrm{t}_{\mathrm{D}}$: Dimensionless Time (dimensionless)

Formula(s)

$$ \mathrm{t}_{\mathrm{D}}=4 *\left(\frac{\mathrm{M}_{\mathrm{s}}}{\mathrm{M}_{\mathrm{R}}}\right)^{2} *\left(\frac{\alpha_{\mathrm{s}}}{h_{t}^{2}}\right) * \mathrm{t} $$

Reference(s)

Prats, M. 1986. Thermal Recovery. Society of Petroleum Engineers, New York, Chapter: 5, Page: 44.