Determination of the controlling resistance

Input(s)

S: Solubility $(\mathrm{mol} / \mathrm{cc})$

M: Mass $(\mathrm{g})$

$\boldsymbol{x}_{\boldsymbol{a}}$: Partial Pressure $(\mathrm{kPa})$

$S_{o}$: Solubility at NTP $(\mathrm{mol} / \mathrm{cc})$

$c_{l}$: Concentration of Liquid $(\mathrm{g} \mathrm{mol} / \mathrm{cc})$

$c_{g}$: Concentration of $\mathrm{Gas}(\mathrm{g} \mathrm{mol} / \mathrm{cc})$

$\boldsymbol{D}_{\boldsymbol{A} \boldsymbol{B}}$: Diffusivity in the Liquid Phase $\left(\mathrm{cm}^{2} / \mathrm{s}\right)$

$\boldsymbol{D}_{\boldsymbol{A} \boldsymbol{C}}$: Diffusivity in the Gas Phase $\left(\mathrm{cm}^{2} / \mathrm{s}\right)$

Output(s)

$\mathrm{m}$: Slope (dimensionless)

R: Resistance (ohm)

Formula(s)

$$ \begin{gathered} m=\frac{S}{M} / \frac{x_{a}}{S_{o}} \\ R=m *\left(\frac{c_{l}}{c_{g}}\right) *\left(\left(\frac{D_{A B}}{D_{A C}}\right)^{0.5}\right) \end{gathered} $$

Reference(s)

Bird, R.B., Stewart, W.E. and Lightfoot, E.N. (2002). Transport Phenomena (Second Ed.). John Wiley \& Sons, Chapter: 22, Page: 691.