Estimating recovery steam drive (volume of steam in reservoir)

Input(s)

$Q_{i}$: Heat Injection Rate $(\mathrm{BTU} / \mathrm{d})$

$\mathrm{t}$: Injection Time $(\mathrm{d})$

$E_{h s}$: Thermal Efficiency of Steam Zone (dimensionless)

$T_{i}$: Injection Temperature $\left({ }^{\circ} \mathrm{F}\right)$

$T_{a}$: Ambient Temperature $\left({ }^{\circ} \mathrm{F}\right)$

Output(s)

$V_{s}$: Gross Volume of Steam in Reservoir (ac ft)

Formula(s)

$$ \mathrm{V}_{\mathrm{s}}=\frac{\mathrm{Q}_{\mathrm{i}} * \mathrm{t} * \mathrm{E}_{\mathrm{hs}}}{38.1 * 43560 *\left(\mathrm{~T}_{\mathrm{i}}-\mathrm{T}_{\mathrm{a}}\right)} $$

Reference(s)

Pratts, M. (1986). Thermal Recovery Monograph Vol. 7. Society of Petroleum Engineers, Houston, Page: 76.